x^2+12x=143

Solution for x^2+12x=143 equation:

x^2+12x=143

We move all terms to the left:

x^2+12x-(143)=0

a = 1; b = 12; c = -143;
Δ = b2-4ac
Δ = 122-4·1·(-143)
Δ = 716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{716}=\sqrt{4*179}=\sqrt{4}*\sqrt{179}=2\sqrt{179}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{179}}{2*1}=\frac{-12-2\sqrt{179}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{179}}{2*1}=\frac{-12+2\sqrt{179}}{2}
$